Re: [tlug] question about shell scripting

["Josh Glover" <jmglov@example.com>]

On 25/01/07, scott@example.com <scott@example.com> wrote:

> I would like to list all of the crotabs for all of the users in the system.
> So first I get a list of users:
>
>    awk -F: '{ print $1 }' /etc/shadow

I would advise hitting /etc/passwd instead of /etc/shadow, just
because it feels more right.

> which is OK. However if I want to use backticks and do something like this:
>
>    crontab -l -u `awk -F: '{ print $1 }' /etc/shadow`

This is equivalent to:

crontab -l -u user1 user2 ... userN

Try feeding two usernames to crontab on the command line and see what happens.

> I thought maybe I could write a for statement in a script this way:
>
>    #!/bin/bash
>    for x in `awk -F: '{ print $1 }' /etc/shadow`;
>    /usr/bin/crontab -l -u $x;
>    done

Close, but no cigar. You left out on minor word that would have made
everything work: "do". Dig this:

for x in `awk -F: '{ print $1 }' /etc/shadow`; do
 /usr/bin/crontab -l -u $x;
done

I added indentation to be nice.

HTH,
Josh