Re: [tlug] [Announcement] August Nomikai 2009

[Bruno Raoult <braoult@example.com>]

On Fri, Aug 14, 2009 at 14:46, Birkir A. Barkarson <birkirb@example.com> wrote:

Bruno Raoult wrote:
> So our logical number: (XXII+I)*II = XLVI

Shouldn't that be I^3(IX^2+1)?

What are we talking about again?

Arghhh... My wife eventually declined :-(

So the answer is probably a division by zero, not sure how to handle this
in Roman numbers :-)

Bruno.

-- 
2 + 2 = 5, for very large values of 2.