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Re: [tlug] ls *++*: What does echo *++* show?
2007/11/6, jep200404 <jep200404@example.com>:
> "Nguyen Vu Hung" wrote:
>
> 〉 [vuhung@ GraphicsMagick-1.1.10]$/bin/ls -F *++*
> 〉 AUTHORS COPYING ChangeLog INSTALL Makefile Makefile.am
> 〉 Makefile.in NEWS README TODO bin/ demo/ lib/ tests/
> 〉 [vuhung@ GraphicsMagick-1.1.10]$
>
> Is there a directory with "++" in its name?
>
> What does echo *++* show?
$ echo *++*
Magick++
This is intersting because "man echo" says:
$ man -k echo
echo (1) - display a line of text
echo [builtins] (1) - bash built-in commands, see bash(1)
$man 1 echo
NAME
echo - display a line of text
$man 1 bash -> " search echo":
echo [-neE] [arg ...]
Output the args, separated by spaces, followed by a
newline. The return status is always 0. If -n is specified, the
trailing newline is suppressed.
If the -e option is given, interpretation of the
following backslash-escaped characters is enabled. The -E option
disables the interpretation of
these escape characters, even on systems where they are
interpreted by default. The xpg_echo shell option may be used to
dynamically determine
whether or not echo expands these escape characters by
default. echo does not interpret -- to mean the end of options. echo
interprets the following
escape sequences:
\a alert (bell)
\b backspace
\c suppress trailing newline
\e an escape character
\f form feed
\n new line
\r carriage return
\t horizontal tab
\v vertical tab
\\ backslash
\0nnn the eight-bit character whose value is the octal
value nnn (zero to three octal digits)
\xHH the eight-bit character whose value is the
hexadecimal value HH (one or two hex digits)
--
Best Regards,
Nguyen Hung Vu
vuhung16plus{remove}@example.com
An inquisitive look at Harajuku
http://www.flickr.com/photos/vuhung/sets/72157600109218238/
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