Re: [tlug] pattern matching

[roy lo <roy730us@example.com>]

for awk

    Pattern="$1"; shift
    awk '{
     if ( match ($0, /'"$Pattern"'/) ) {
  print substr ($0, RSTART, RLENGTH)
     }
}
    ' "$@"

isn't google great :P

 "Stephen J. Turnbull" wrote:

>>>>> "Brett" == Brett Robson writes:

Brett> I want to grep for a pattern but I don't want to see the
Brett> whole line, just the bit that matches. Sometimes I pipe to
Brett> cut but in this case I don't know where the pattern will
Brett> be. Surely this is straight forward?

grep -e 'PATTERN' | sed -e 's/.*\(PATTERN\).*/\1/'
perl -ane 'print "$&\n" if /PATTERN/'

There must be a way of doing this using awk, but I can't remember it.


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ask what your business can "do for" free software.

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