Re: java question

[James Gibson <twistedhammer@example.com>]

Quoting Fredric Fredricson <fredric.fredriksson@example.com>:

> B0Ti wrote:
> > 
> > Evening,
> > 
> > Maybe it's trivial, but I cannot find a clean solution to this.
> > I need to read in an integer and it must be within a limit. Something
> > like this:
> > 
> > try {
> >     int someInt = Integer.parseInt(readUserInput());
> >     if (someInt > 10 || someInt < 0) throw new NumberFormatException;
> > }
> > catch (NumberFormatException) { /* goto begin :( ...*/ }
> > 
> > My problem is that when NumberFormatException is caught I need to go
> > back (restart at try)  and read in the integer again.
> > Having grown up on basic I would immediately use a goto statement if
> > java would allow it.
> > How should this be done cleanly and effectively?
> 
> Just a small observation: just because java has exceptions does not 
> mean that they are good for everything. Maybe a solution without
> exceptions would be cleaner in this particular case.
> 
> /Fredric Fredricson

Been too long since I've used java to give you particulars... however,
here's the basic idea for something like this using C style psuedo-code,
and no exception handling... 

while(TRUE) {                   #loop endlessly
    someInt = readUserInput();  #get input
    if (isLegal(someInt)) {     #if input is legal
       break;                   #then exit.loop
    }                           #otherwise,
}                               #start over
   
Also, if GOTO is still a gut reaction, you might want to read up some
more on C-style looping mechanisms such as this.

James Gibson
twistedhammer@example.com


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