Re: REGEXP in perl questiion

[Matt Doughty <mdoughty@example.com>]

On Wed, May 23, 2001 at 08:44:31AM -0000, Jean-Christian Imbeault wrote:
> Ok, I admint it's lazy but could someone give me a regular expression in 
> Perl that would do the following? (I've tried for the last hour but I'm not 
> very good at regular expressions it seems).
> 
> I have strings like the following:
> 
> Subject: Cron <root@example.com> /root/AdminScripts/NSH.sh
> Subject: Cron <root@example.com> /usr/bin/rsync -avzr --delete 
> /home/httpd/html/top40/* 10.0.1.53:/home/httpd/html/
> 
> I want to extract the name of the program that cron started, without the 
> switches if any.
> 
> I've tried this but it's greedy and doesn't extarct *just* the prog name but 
> also the switches ... I tought the " .*?" would cause lazy expansion but 
> it's not working as I had hoped.
> 
> if ( $_ =~ /^Subject: /) {
>   if ($_ =~ "Cron") {
>     $CRON_EMAIL = 1;
		#after some thought it occured to me this is better done with split 
      #because the format is regular:
		#strip leading spaces
		s/^\s*//;
      #first split breaks it up based on whitespace
		#the second based on /'s
		$PROGNAME = (split(/\//, (split(/\s+/))[3]))[-1];
>     print "The program called by cron was $PROGNAME\n";
>   }
> }
> 
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